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Double Factorial
ID: 771; easy; 二阶阶乘
public class Solution {
/**
* @param n: the given number
* @return: the double factorial of the number
*/
public long doubleFactorial(int n) {
if (n == 0 || n == 1) return 1;
return (long)n * doubleFactorial(n - 2);
}
}
- By definition of double factorial, the result is immediate.
Last modified 2yr ago