Lowest Common Ancestor of a Binary Tree

ID: 88; medium

LintCode 炼码

Solution 1 (Java)

/**
 * Definition of TreeNode:
 * public class TreeNode {
 *     public int val;
 *     public TreeNode left, right;
 *     public TreeNode(int val) {
 *         this.val = val;
 *         this.left = this.right = null;
 *     }
 * }
 */


public class Solution {
    /*
     * @param root: The root of the binary search tree.
     * @param A: A TreeNode in a Binary.
     * @param B: A TreeNode in a Binary.
     * @return: Return the least common ancestor(LCA) of the two nodes.
     */
    public TreeNode lowestCommonAncestor(TreeNode root, TreeNode A, TreeNode B) {
        if (root == null)
            return null;
        if (root == A || root == B)
            return root;

        TreeNode left = lowestCommonAncestor(root.left, A, B);
        TreeNode right = lowestCommonAncestor(root.right, A, B);
        if (left != null && right != null)
            return root;
        if (left != null)
            return left;
        if (right != null)
            return right;
        
        return null;
    }
}

Notes

There are 4 general cases.

1. If root is A or B, we directly return the root since both A and B are guaranteed to be in the tree. If the root is one of them, then the other one must be its descendent.

2. If A and B are on the different sides of the root, then the root of the LCA.

3. If A and B are both in the left tree, then we find the LCA of the left tree.

4. If A and B are both in the right tree, then we find the LCA of the right tree.