Convert Sorted Array to Binary Search Tree

ID; 108; easy

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Solution 1

/**
 * Definition for a binary tree node.
 * type TreeNode struct {
 *     Val int
 *     Left *TreeNode
 *     Right *TreeNode
 * }
 */
func sortedArrayToBST(nums []int) *TreeNode {
    if len(nums) == 0 {
        return nil
    }
    n := TreeNode{
        Val: nums[len(nums)/2],
        Left: sortedArrayToBST(nums[:len(nums)/2]),
        Right: sortedArrayToBST(nums[len(nums)/2+1:]),
    }
    return &n
}