ID: 112; easy
Last updated 3 years ago
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/** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */ func hasPathSum(root *TreeNode, targetSum int) bool { if root == nil { return false } if root.Left == nil && root.Right == nil { return root.Val == targetSum } curVal := targetSum - root.Val return hasPathSum(root.Left, curVal) || hasPathSum(root.Right, curVal) }